6x^2+50x-1350=0

Solution for 6x^2+50x-1350=0 equation:

6x^2+50x-1350=0

a = 6; b = 50; c = -1350;
Δ = b2-4ac
Δ = 502-4·6·(-1350)
Δ = 34900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{34900}=\sqrt{100*349}=\sqrt{100}*\sqrt{349}=10\sqrt{349}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-10\sqrt{349}}{2*6}=\frac{-50-10\sqrt{349}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+10\sqrt{349}}{2*6}=\frac{-50+10\sqrt{349}}{12}
$